如何输入一行字符,分别统计出其中英文字母,空格？
2024-06-22 03:30:25
错误代码：
if('a'<=nextchar<='z'||'A'<=nextchar<='Z')
else if('0'<=nextchar<='9')
修改后：
#include <stdio.h>
int main()
{
int letter=0,space=0,number=0,others=0;
char nextchar;
printf("Input your string\n");
for(;nextchar!='\n';)
{
scanf("%c",&nextchar);
if('a'<=nextchar&&nextchar<='z'||'A'<=nextchar&&nextchar<='Z')
letter++;
else if(nextchar==' ')
space++;
else if('0'<=nextchar&&nextchar<='9')
number++;
else
others++;
}
printf("letter=%d,space=%d,number=%d,others=%d\n",letter,space,number,others);
}
c++输入一行字符，分别统计出其中英文字母、空格、数字和其他字符的个数。
#include<cstdio>
int main()
{
char x[999];
int i,a=0,b=0,c=0,d=0;
gets(x);
for(i=0;i<=x[i];i++)
{
if('A'<=x[i]&&x[i]<='z')
a++;
else if('0'<=x[i]&&x[i]<='9')
b++;
else if(x[i]==' ')
c++;
else
d++;
}
printf("%d %d %d %d\n",a,b,c,d);
return 0;
}
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