输入一行字符,分别统计出其中的英文字母.空格.数字.和其他字符的个数!
为什么运行的时候显示的答案不正确呢 555555555555555555
最新回答
下一站の調情
2024-04-26 00:15:58
#include <ctype.h> /*for type hceck*/
#include <string.h>/*for strlen()*/
int main()
{
int i;
unsigned letters = 0; /*字母*/
unsigned spaces = 0; /*空格*/
unsigned digits = 0; /*数字*/
unsigned others = 0; /*其他*/
char line[256];
printf("Enter a line of words: \n");
gets(line);
for(i = 0; i < strlen(line); ++i)
{
if(isalpha(line[i]))
++letters;
else if(isspace(line[i]))
++spaces;
else if(isdigit(line[i]))
++digits;
else
++others;
}
printf("The line you entered has:\n");
printf("%d letters\n", letters);
printf("%d spaces\n", spaces);
printf("%d digits\n", digits);
printf("%d others\n", others);
}
下一站↘婞諨
2024-04-26 00:08:19
#include <string.h>
void main()
{
char a[1000], i, x1, x2, x3, x4;
scanf("%s", a);
x1 = 0; x2 = 0; x3 = 0; x4 = 0;
for (i = 0; i < strlen(a); i++)
if (((a[i] >='a') && (a[i] <= 'z')) || ((a[i] >='A') && (a[i] <= 'Z'))) x1 ++;
else if (a[i] == ' ') x2++;
else if ((a[i] >= '0') && (a[i] <= '9')) x3++;
else x4++;
printf("%d %d %d %d\n", x1, x2, x3, x4);
}
唯美╮似夏花
2024-04-26 02:50:59
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