java中正则表达式的问题 零宽断言的
String[] a= x.split(regx3);
结果报红字错
(?<=0x\d+)|(?<=0X\d+)
^
at java.util.regex.Pattern.error(Unknown Source)
at java.util.regex.Pattern.group0(Unknown Source)
at java.util.regex.Pattern.sequence(Unknown Source)
at java.util.regex.Pattern.expr(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.util.regex.Pattern.<init>(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.lang.String.split(Unknown Source)
at java.lang.String.split(Unknown Source)
at Regex.analytical(two.java:12)
at two.main(two.java:53)
最新回答
软耳兔兔
2024-11-26 03:42:28
split方法虽然是用正则表达式实现的，但不能这么用。另外这个零宽断言有问题，我改了一下，不知道是不是你想要的。程序如下：
Pattern pattern = Pattern.compile("(?<=0x)\\d+|(?<=0X)\\d+");
Matcher matcher = pattern.matcher(x);
while (matcher.find()) {
System.err.println(matcher.group());
}
叆叇若紫
2024-11-26 04:48:02
追问
可是零宽度正回顾后发断言的愈发格式的确是这样啊.....
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