C# listbox控件 显示数据表中的数据
最新回答
妖孽只在夜里哭
2024-10-02 02:20:15
Source=;\.Open();
sqlcon
=
new
SqlConnection(",
sqlcon)SqlConnection
sqlcon;);
SqlDataAdapter
sqlada;
sqlcon.DisplayMember
=
"
sqlada
=
new
SqlDataAdapter(str;
string
str
=
"
很简单的一个绑定
;
listBox1..Fill(a).;press;goodsname1".希望能帮到你;;Initial
Catalog=HQZPOSDB;.DefaultView;
DataSet
a
=
new
DataSet();
sqlada.DataSource
=
a;User
ID=sa.Tables[0];Password=zenii"goodsname1".ValueMember
=
"select
goodsname1
from
goods";
listBox1;
listBox1.\
时光让我们忘记模样
2024-10-02 00:44:28
SqlDataAdapter sqlada;
sqlcon = new SqlConnection("Data Source=.\\press;Initial Catalog=HQZPOSDB;User ID=sa;Password=zenii");
sqlcon.Open();
string str = "select goodsname1 from goods";
sqlada = new SqlDataAdapter(str, sqlcon);
DataSet a = new DataSet();
sqlada.Fill(a);
listBox1.DisplayMember = "goodsname1";
listBox1.ValueMember = "goodsname1";
listBox1.DataSource = a.Tables[0].DefaultView;
很简单的一个绑定 ..希望能帮到你..
凤舞九天
2024-10-02 01:31:42
说的就可以
你把他说的写进事件里 他点100次 也是生成1次
瑾色如弦
2024-10-02 02:06:53
SqlDataAdapter sqlada;
sqlcon = new SqlConnection("Data Source=.\\press;Initial Catalog=HQZPOSDB;User ID=sa;Password=zenii");
sqlcon.Open();
string str = "select goodsname1 from goods";
sqlada = new SqlDataAdapter(str, sqlcon);
DataSet a = new DataSet();
sqlada.Fill(a);
listBox1.DisplayMember = "goodsname1";
listBox1.ValueMember = "goodsname1";
listBox1.DataSource = a.Tables[0].DefaultView;
残●沐伊丶
2024-10-02 01:51:42
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