swift中如何比较String对象
最新回答
一身傲气怎能服输
2024-09-22 00:09:28
字符串
的值：字符串相等、前缀相等和后缀相等。1，字符串相等
如果两个字符串以同一顺序包含完全相同的字符，则认为两者字符串相等：
let quotation = "我们是一样一样滴."
let sameQuotation = "我们是一样一样滴."
if quotation == sameQuotation {
println("这两个字符串被认为是相同的")
}
// 打印输出："这两个字符串被认为是相同的"
2，前缀/后缀相等 (Prefix and Suffix Equality)
通过调用字符串的hasPrefix/hasSuffix方法来检查字符串是否拥有特定前缀/后缀。 两个方法均需要以字符串作为参数传入并传出Boolean值。 两个方法均执行基本字符串和前缀/后缀字符串之间逐个字符的比较操作。
下面的例子以一个字符串数组表示
莎士比亚
话剧《罗密欧与朱丽叶》
中前两场的场景位置：let romeoAndJuliet = [
"Act 1 Scene 1: Verona, A public place",
"Act 1 Scene 2: Capulet's mansion",
"Act 1 Scene 3: A room in Capulet's mansion",
"Act 1 Scene 4: A street outside Capulet's mansion",
"Act 1 Scene 5: The Great Hall in Capulet's mansion",
"Act 2 Scene 1: Outside Capulet's mansion",
"Act 2 Scene 2: Capulet's orchard",
"Act 2 Scene 3: Outside Friar Lawrence's cell",
"Act 2 Scene 4: A street in Verona",
"Act 2 Scene 5: Capulet's mansion",
"Act 2 Scene 6: Friar Lawrence's cell"
]
您可以利用hasPrefix方法来计算话剧中第一幕的场景数：
var act1SceneCount = 0
for scene in romeoAndJuliet {
if scene.hasPrefix("Act 1 ") {
++act1SceneCount
}
}
println("There are \(act1SceneCount) scenes in Act 1")
// 打印输出："There are 5 scenes in Act 1"
相似地，您可以用hasSuffix方法来计算发生在不同地方的场景数：
var mansionCount = 0
var cellCount = 0
for scene in romeoAndJuliet {
if scene.hasSuffix("Capulet's mansion") {
++mansionCount
} else if scene.hasSuffix("Friar Lawrence's cell") {
++cellCount
}
}
println("\(mansionCount) mansion scenes; \(cellCount) cell scenes")
// 打印输出："6 mansion scenes; 2 cell scenes”
参考连接：
http://www.yiibai.com/swift/comparing_strings.html
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