兄弟帮我讲解下，"12345" "27462" java正则表达式如何匹配双引号引起来的5位数字，完全匹配。求大神？
比如说字符串nfwenlwkngkwleknkwk"12345"nlkknflkwenfk“43678”wefnw0-0-0 我要打印出12345和43678这两个数字"12345" "27462" java正则表达式如何匹配双引号引起来的5位数字，完全匹配。求大神
最新回答
心头的小情儿
2024-07-28 05:07:17
package cn.test;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Test {
public static void orFind(String regexString){
Pattern pattern = Pattern.compile("“\\d{5}”");
Matcher matcher = pattern.matcher(regexString);
String temp = "" ;
while(matcher.find()){
temp = matcher.group().replaceAll("“", "").replaceAll("”", "");
System.out.println(temp);
}
}
public static void main(String[] args) {
String regexString = "nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk\"43678\"“12345”wefnw0-0-0" ;
Pattern pattern = Pattern.compile("\"\\d{5}\"");
Matcher matcher = pattern.matcher(regexString);
String temp = "" ;
while(matcher.find()){
temp = matcher.group().replaceAll("\"", "");
System.out.println(temp);
}
orFind(regexString);
}
}
//不多说什么，运行结果说话；记得java的字符串中用到双引号“”要用\"转义的
追问
谢谢你！
接住路过的风
2024-07-28 02:44:33
测试通过，任意用！
Pattern pattern = Pattern.compile("[\"“]{1}(\\d{5})[\"”]{1}");
Matcher macher = pattern.matcher("nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk“43678”wefnw0-0-01232");
while (macher.find())
{
System.out.println(macher.group(1));
}
追问
谢谢，正则很好!我点错了最佳答案的。。。
追答
没关系，能帮上你就可以了
酒爷
2024-07-28 05:53:28
public static void main(String[] args) {
String s = "nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk“43678”wefnw0-0-0";
Pattern pattern = Pattern.compile("\\d{5}");
Matcher m = pattern.matcher(s);
while (m.find()) {
System.out.println(m.group(0));
}
}
追问
字符串里面还有其他另外的数字呢，比如我要取{"i":"20130902-034","b":"77200"},{"i":"20130902-035","b":"83584"},{"i":"20130902-036","b":"27530"}这个字符串里面的 77200 83584 27530 这三个数字
追答
你只要把这个字符串当作参数传到pattern.matcher()方法中就可以了
Matcher m = pattern.matcher("{\"i\":\"20130902-034\",\"b\":\"77200\"},{\"i\":\"20130902-035\",\"b\":\"83584\"},{\"i\":\"20130902-036\",\"b\":\"27530\"}");
春夜浅
2024-07-28 00:45:14
Matcher ma=pa.matcher("nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk“43678”wefnw0-0-0");
while(ma.find()){
System.out.println(ma.group());
}
追问
貌似不行呢 比如我要取{"i":"20130902-034","b":"77200"},{"i":"20130902-035","b":"83584"},{"i":"20130902-036","b":"27530"}这个字符串里面的 77200 83584 27530 这三个数字
追答
public static void test1( ) {
Pattern pa=Pattern.compile("\\d{5}");
Matcher ma=pa.matcher("nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk“43678”wefnw0-0-0");
while(ma.find()){
System.out.println(ma.group());
}
ma=pa.matcher("{\"i\":\"20130902-034\",\"b\":\"77200\"},{\"i\":\"20130902-035\",\"b\":\"83584\"},{\"i\":\"20130902-036\",\"b\":\"27530\"}");
while(ma.find()){
System.out.println(ma.group());
}
}
Process started >>>
12345
43678
20130
77200
20130
83584
20130
27530
<<< Process finished. (Exit code 0)
追问
大哥 20130这个不应该打印的呀
追答
Pattern pa=Pattern.compile("\\D\\d{5}\\D");
Pattern pa2=Pattern.compile("\\d{5}");
Matcher ma=pa.matcher("nfwenlwkngkwleknkwk\"12345\"nlkknflkwenfk“43678”wefnw0-0-0");
while(ma.find()){
Matcher ma2=pa2.matcher(ma.group());
while(ma2.find()){
System.out.println(ma2.group());
}
}
ma=pa.matcher("{\"i\":\"20130902-034\",\"b\":\"77200\"},{\"i\":\"20130902-035\",\"b\":\"83584\"},{\"i\":\"20130902-036\",\"b\":\"27530\"}");
while(ma.find()){
Matcher ma2=pa2.matcher(ma.group());
while(ma2.find()){
System.out.println(ma2.group());
}
}
Process started >>>
12345
43678
77200
83584
27530
<<< Process finished. (Exit code 0)
浪菊怪哟
2024-07-28 08:38:51
追问
字符串中还包含其他无引号引起来的数字
追答
String text = "nfwenlwkngkwleknkwk“12345”nlkknflkwenfk“43678”wefnw0-0-0";
Pattern pattern = Pattern.compile("[0-9]{5}");
Matcher matcher = pattern
.matcher(text);
while (matcher.find()) {
System.out.println(matcher.group());
}
你的字符串我将双引号改成中文的了，上面的那位也是对的.
如果数字0也要的话就将[0-9]+或\\d+
Pattern pa = Pattern.compile("[0-9]+");
Matcher ma = pa
.matcher("nfwenlwkngkwleknkwk1234523”nlkknflkwenfk“43678”wefnw0-0-0");
while (ma.find()) {
if(ma.group().length()==5){
System.out.println(ma.group());}
}
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谢谢！
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