c语言从键盘输入一字符串
最新回答
▎黎子°
2024-07-03 00:56:09
int main()
{
char str[100];
long long an[100];
int cnt=0,i=0,f=0;
printf("Please input a string:");
gets(str);
while(str[i])
{
if(str[i]>='0'&&str[i]<='9')
{
if(f==1)
{
an[cnt]=an[cnt]*10+str[i]-'0';
}
if(f==0)
{
cnt++;
f=1;
an[cnt]=str[i]-'0';
}
}
else
{
f=0;
}
i++;
}
if(cnt==0)
{
printf("None\n");
}
else
{
printf("Total number: %d\n",cnt);
for(i=1;i<=cnt;i++)
{
printf("%lld*2=%lld\n",an[i],an[i]*2);
}
}
return 0;
}
山水闲人
2024-07-03 01:57:22
void main()
{
char str[81];
long num[40];
long n;
int cnt=0;
int i;
gets(str);
for(i=0;str[i];i++)
{
n=0;
if(str[i]>='0' && str[i]<='9')
{
while(str[i] && str[i]>='0' && str[i]<='9')
{
n=n*10+str[i]-'0';
i++;
}
num[cnt++]=n*2;
}
}
if(cnt)
{
printf("%d个数\n",cnt);
for(i=0;i<cnt;i++)
printf("%ld ",num[i]);
}
else
printf("None.\n");
}
﹏空白
2024-07-03 01:40:17
void print_num(char *str)
{
char string[20][20];
int i=0,num=0,new_num=0,counter=0;
while(*(str+i))//即*(str+i)!='\0'
{
if(*(str+i)>='0'&&*(str+i)<='9'&&new_num==0)
{
string[num][counter]=*(str+i);
counter++;
new_num=1;
}
else if(*(str+i)>='0'&&*(str+i)<='9'&&new_num==1)
{
string[num][counter]=*(str+i);
counter++;
}
else if((*(str+i)<'0'||*(str+i)>'9')&&new_num==1)
{
string[num][counter]='\0';
new_num=0;
num++;
counter=0;
}
else if((*(str+i)<'0'||*(str+i)>'9')&&new_num==0);
i++;
}
string[num][counter]='\0';
num=num+1;
printf("there are %d num.\nthere are:\n",num);
for(i=0;i<num;i++)
puts(string[i]);
}
int main()
{
char string[100],*str;
printf("Please enter a string:\n");
gets(string);
str=string;
print_num(str);
return 0;
}
至于每个整数*2，可以作为练习来做，可以好好看一下这个代码，值得思考的
秋桜
2024-07-03 04:17:30
#include <string.h>
#include <stdlib.h>
void main()
{
char str[80];
int i;
int j = 0;
int nFlag = 0;
int count = 0;
int a[20];
scanf("%s", str);
for (i = 0; i < strlen(str); i++)
{
if (str[i] >= '0' && str[i] <= '9' && nFlag == 0)
{
count++;
a[j] = atoi(str + i);
j++;
nFlag = 1;
}
else
{
nFlag = 0;
}
}
if (count == 0)
{
printf("None\n");
}
printf("%d ", count);
for (i = 0; i < j; i++)
{
printf("%d ", 2 * a[i]);
}
}
下一站の調情
2024-07-03 05:09:25
12 31 534 77 91
2 × 12 = 24
2 × 31 = 62
2 × 534 = 1068
2 × 77 = 154
2 × 91 = 182
n
n = 5
Press any key to continue
*/
#include <stdio.h>
int main() {
int num,n = 0;
while(scanf("%d",&num) == 1) {
++n;
printf("2 × %d = %d\n",num,2*num);
}
if(n == 0) printf("None.\n");
else printf("\nn = %d\n",n);
return 0;
}
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