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简介
pycurl类似于Python的urllib,但是pycurl是对libcurl的封装,速度更快。
本文使用的是pycurl 7.43.0.1版本。
Apache下配置Basic认证
生成basic密码文件
htpasswd -bc passwd.basic test 123456
开启mod_auth_basic
LoadModule auth_basic_module modules/mod_auth_basic.so
配置到具体目录
<Directory "D:/test/basic"> AuthName "Basic Auth Dir" AuthType Basic AuthUserFile conf/passwd.basic require valid-user </Directory>
重启Apache
Apache下配置Digest认证
生成Digest密码文件
htdigest -c passwd.digest "Digest Encrypt" test
开启mod_auth_digest
LoadModule auth_digest_module modules/mod_auth_digest.so
配置到具体目录
<Directory "D:/test/digest"> AuthType Digest AuthName "Digest Encrypt" # 要与密码的域一致 AuthDigestProvider file AuthUserFile conf/passwd.digest require valid-user </Directory>
重启Apache
验证Basic认证
# -*- coding: utf-8 -*- import pycurl try: from io import BytesIO except ImportError: from StringIO import StringIO as BytesIO buffer = BytesIO() c = pycurl.Curl() c.setopt(c.URL, 'http://test/basic/') c.setopt(c.WRITEDATA, buffer) c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC) c.setopt(c.USERNAME, 'test') c.setopt(c.PASSWORD, '123456') c.perform() print('Status: %d' % c.getinfo(c.RESPONSE_CODE)) print(buffer.getvalue()) c.close()
验证Digest认证
# -*- coding: utf-8 -*- import pycurl try: from io import BytesIO except ImportError: from StringIO import StringIO as BytesIO buffer = BytesIO() c = pycurl.Curl() c.setopt(c.URL, 'http://test/digest/') c.setopt(c.WRITEDATA, buffer) c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST) c.setopt(c.USERNAME, 'test') c.setopt(c.PASSWORD, '123456') c.perform() print('Status: %d' % c.getinfo(c.RESPONSE_CODE)) print(buffer.getvalue()) c.close()
本文python pycurl验证basic和digest认证的方法到此结束。早晨不起,误一天的事,幼时不学,误一生的事。小编再次感谢大家对我们的支持!