PostgreSQL 查找当前数据库的所有表操作

实现的功能类似MySQL:show tables;在 PostgreSQL 中需要写:select * from pg_tables where scheman

实现的功能类似MySQL:

show tables;

在 PostgreSQL 中需要写:

select * from pg_tables where schemaname = 'public';

返回结果类似如下:

schemaname | tablename | tableowner | tablespace | hasindexes | hasrules | hastriggers | rowsecurity 
------------+-----------+------------+------------+------------+----------+-------------+-------------
 public  | deploy | postgres |   | t   | f  | f   | f
 public  | deploy2 | postgres |   | f   | f  | f   | f
(2 rows)

补充:PostgreSql 获取所有的表、视图、字段、 主键

PostgreSQL获取数据库中所有view名 视图:

SELECT viewname FROM pg_views 
WHERE  schemaname ='public' 

postgreSQL获取数据库中所有table名 表:

SELECT tablename FROM pg_tables 
WHERE tablename NOT LIKE 'pg%' 
AND tablename NOT LIKE 'sql_%'
ORDER BY tablename;

postgreSQL获取某个表tablename 所有字段名称 , 类型,备注,是否为空 等

SELECT col_description(a.attrelid,a.attnum) as comment,pg_type.typname as typename,a.attname as name, a.attnotnull as notnull
FROM pg_class as c,pg_attribute as a inner join pg_type on pg_type.oid = a.atttypid
where c.relname = 'tablename' and a.attrelid = c.oid and a.attnum>0

postgreSQL获取某个表tablename 的主键信息

select pg_attribute.attname as colname,pg_type.typname as typename,pg_constraint.conname as pk_name from 
pg_constraint inner join pg_class 
on pg_constraint.conrelid = pg_class.oid 
inner join pg_attribute on pg_attribute.attrelid = pg_class.oid 
and pg_attribute.attnum = pg_constraint.conkey[1]
inner join pg_type on pg_type.oid = pg_attribute.atttypid
where pg_class.relname = 'tablename' 
and pg_constraint.contype='p'

以上为个人经验,希望能给大家一个参考,也希望大家多多支持好代码网。如有错误或未考虑完全的地方,望不吝赐教。