C语言代码如何实现井字棋游戏

发布时间：2024-04-09 11:47:26 来源：网络

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井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“ ”棋子，谁先连成3个，谁就赢。本次使用C语言来实现这个小游戏。由于使用

井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“#”棋子，谁先连成3个，谁就赢。

本次使用C语言来实现这个小游戏。

由于使用函数较多，所以采用多文件的方式方便梳理代码思路。

本次一共有三个文件：

**

game.h：

包含了game.c文件中函数的声明和库函数的声明。**

#pragma once

#define ROW 3
#define COL 3

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

void InitBoard(char board [ROW][COL], int row, int col); //初始化棋盘

void DisplayBoard(char board [ROW][COL], int row, int col); //打印棋盘

void PlayerBoard(char board [ROW][COL], int row, int col); //玩家走

void ComputerBoard(char board [ROW][COL], int row, int col);//电脑走

char IsWin(char board [ROW][COL], int row, int col); //结果判断

game.c：

包含游戏过程中关键函数的函数主体。

#define _CRT_SECURE_NO_WARNINGS

#include"game.h"

void InitBoard(char board[ROW][COL], int row, int col)
{
 //初始化棋盘
 int i = 0;
 for (i = 0; i < row; i++)
 {
  int j = 0;
  for (j = 0; j < col; j++)
   board [i][j] = ' ';
 }
}

void DisplayBoard(char board [ROW][COL], int row, int col)
{
 //打印棋盘
 int i = 0;
 for (i = 0; i < row; i++)
 {
  int j = 0;
  for (j = 0; j < col; j++)
  {
   printf(" %c ", board [i][j]);
   if (j < col - 1)
    printf("|");
  }
  printf("\n");

  if (i < row - 1)
  {
   for (j = 0; j < col; j++)
   {
    printf("---");
    if (j < col - 1)
     printf("|");
   }
   printf("\n");
  }
 }
}

void PlayerBoard(char board [ROW][COL], int row, int col)
{
 int x = 0, y = 0;
 while (1)
 {
  printf("输入棋子坐标->");
  scanf("%d%d", &x, &y);
  if (x > 0 && x <= row && y > 0 && y <= col)
  {
   if (board [x - 1][y - 1] == ' ')
   {
    board [x - 1][y - 1] = '*';
    break;
   }
   else
   {
    printf("此位置已有棋子！请重新输入。\n");
   }
  }
  else
  {
   printf("输入错误！请重新输入。\n");
  }
 }
}

void ComputerBoard(char board [ROW][COL], int row, int col)
{
 int x = 0, y = 0;
 while (1)
 {
  x = rand() % row;
  y = rand() % col;
  if (board [x][y] != ' ')
  {
   continue;
  }
  else
  {
   board [x][y] = '#';
   break;
  }
 }
}

int IsFull(char board [ROW][COL], int row, int col)
{
 int i = 0;
 for (i = 0; i < row; i++)
 {
  int j = 0;
  for (j = 0; j < col; j++)
  {
   if (board [i][j] == ' ')
    return 0;
  }
 }
 return 1;
}

char IsWin(char board [ROW][COL], int row, int col)
{
 int i = 0;
 //行
 for (i = 0; i < row; i++)
 {
  if (board [i][0] == board [i][1] && board [i][1] == board [i][2] && board [i][0] != ' ')
   return board [i][0];
 }
 //列
 for (i = 0; i < col; i++)
 {
  if (board [0][i] == board [1][i] && board [1][i] == board [2][i] && board [0][i] != ' ')
   return board [0][i];
 }
 //对角线
 if (board [0][0] == board [1][1] && board [1][1] == board [2][2] & board [1][1] != ' ')
  return board [1][1];
 if (board [2][0] == board [1][1] && board [1][1] == board [0][2] & board [1][1] != ' ')
  return board [1][1];
 //是否平局
 if (IsFull(board, row, col))
  return 'Q';//平局
 return 'C';//继续
}

test.c：

main函数和游戏的大概流程。

#define _CRT_SECURE_NO_WARNINGS

#include"game.h"

void Menu()
{
 printf("*******************************\n");
 printf("**********  1、play  **********\n");
 printf("**********  0、quit  **********\n");
 printf("*******************************\n");
}

void game()
{
 char board [ROW][COL];
 InitBoard(board, ROW, COL);
 DisplayBoard(board, ROW, COL);
 char ret = 0;

 srand((unsigned int) time(NULL));
 while (1)
 {
  printf("玩家走\n");
  PlayerBoard(board, ROW, COL);
  DisplayBoard(board, ROW, COL);

  ret = IsWin(board, ROW, COL);
  if (ret != 'C')
   break;
   
  printf("电脑走\n");
  ComputerBoard(board, ROW, COL);
  DisplayBoard(board, ROW, COL);

  ret = IsWin(board, ROW, COL);
  if (ret != 'C')
   break;

 }
 if (ret == '*')
  printf("玩家胜利！\n");
 else if (ret == '#')
  printf("电脑胜利！\n");
 else
  printf("平局！\n");
}

int main()
{
 //三子棋
 int input = 1;
 while (input)
 {
  Menu();
  printf("输入1开始游戏，输入0退出游戏。\n请输入->");
  scanf("%d", &input);
  switch(input)
  {
   case 1:
    game();
    printf("开始游戏\n");
    break;
   case 0:
    printf("游戏结束\n");
    break;
   default:
    printf("非法输入，请重试！\n");
  }  
 }
 return 0;
}

运行图片